Answered

what is the coordinate of the vertex for the following prabola: (x-10)^2 = 12(y+2)

Answer :

CAYLUSGO

Answer:

Hi,

Step-by-step explanation:

[tex](x-10)^2=12(y+2)\\y=\dfrac{(x-10)^2}{12}-2\\y'=0 == > 2(x-10)/12=0 == > x=10 == > y=-2\\\\Vertex\ is\ (10,-2)\\[/tex]

Go Question: Other Questions