Answered

A child stands on the edge of a merry-go-round of radius 1.63 m which is rotating at 2.13 rad/s.
The merry-go-round then slows down to a stop in 26.9 s.
While coming to a stop, how many revolutions will the merry-go-round make?

Answer :

Answer:

9

Explanation:

2.13 rad/s * 26.9 sec

2.13 * 26.9

57.297

3282.88 deg / 360 deg = 9.12

It makes 9 complete revolutoins

View image YULTHENINJA

Go Question: Other Questions