Answer:
h = 1/616 ≈.002 cm
Step-by-step explanation:
V of a cylinder = Area of the circle · height of the cylinder
A of the circle = π·r² = π·(d/2)² = (22/7)·(28/2)² = 616 cm³
If the V of the cylinder = 1 liter and the Area of the circle = 616 cm³ then
What is the height of the cylinder?
V of a cylinder = Area of the circle · height of the cylinder
V of a cylinder / Area of the circle = height of the cylinder
1/616 = height of the cylinder
Height of the cylinder that is lowered when 1 liter of water is drawn is
h = 1/616 ≈.002 cm
