Cone A is divided into Cone B and Frustum C. B A 12cm C 20cm 20cm Express the volume of Frustum C as a fraction of the volume of Cone A. Give your answer in its simplest form.

The volume of the frustum is volume of the whole cone(A) minus the smaller cone(B) which is would give the volume of frustum(C) = 256cm³
The volume of cone A V=πr²h/3
Where radius = 20cm
The volume of cone B = V=πr²h/3
Where radius = 12cm
Therefore volume of frustum =
V=π * 20² * h/3 - π * 12² *h/3
The variables will cancel out each other
V = 20² - 12²
V = 400- 144
V = 256cm³
Therefore, the volume of the frustum(C) = 256cm³
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