What is the temperature (in °C) if 12.1 g of N2 in a 1.3 L container has a pressure of 5.8 atm?

Answer:
T=-166.8 C
Explanation:
PM=m/vRT
T=PMV/mR
T=5.8*14*1.3/12.1*0.08206
T=106.3K
=106-273.15=-166.8 C