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A capacitor is connected across an ac source. suppose the frequency of the source is doubled. what happens to the capacitive reactance of the capacitor?.

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Explanation:

The capacitive reactance of the capacitor is determined by [tex]X_{C}=\frac{1}{\omega C}[/tex]

When [tex]f'=2f \rightarrow \omega' =2\omega[/tex]

and [tex]X_{C}'=\frac{1}{2}X_{C}[/tex]

(The capacitive reactance will be reduced into 1/2 times of the previous capacitive reactance)

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