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A dock worker uses a pulley system to raise a boat onto a dock. the pulley system has a mechanical efficiency of 73 %. the boat has a weight of 950 n. the pulley system lifts the boat 5 m into the air. how many newton-metres of work does the dock worker have to exert to lift the boat?

Answer :

EDUARD22SLYGO

The work (newton-metres) the dock worker have to exert to lift the boat to 5 m in air is 6506.85 Nm

What is work done?

This is simply defined as the product of force and distance moved in the direction of the force. Mathematically, it can be expressed as

Workdone (Wd) = force (F) × distance (d)

Wd = Fd

How to determine the output work done

  • Force (F) = 950 N
  • Distance (d) = 5 m
  • Output work =?

Output work = Fd

Output work = 950 × 5

Output work = 4750 Nm

How to determine the input work done

  • Output work = 4750 Nm
  • Efficiency = 73%
  • Input work =?

Efficiency = (output / input) × 100

73% = 4750 / input

0.73 = 4750 / input

Cross multiply

0.73 × input = 4750

Divide both side by 0.73

Input work = 4750 / 0.73

Input work = 6506.85 Nm

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