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The solubility of a gas is 0.890 g/L at a pressure of 120 kPa. What is the solubility of the gas if the pressure is changed to 100 kPa, given that the temperature is held constant?

Answer :

OKPALAWALTER8GO

For the solubility of a gas is 0.890 g/L at a pressure of 120 kPa, the solubility of the gas, if the pressure is changed to 100 kPa is mathematically given as

c=0.741g/l

What is the solubility of the gas if the pressure is changed to 100 kPa, given that the temperature is held constant?

Generally, the equation for the Pressure   is mathematically given as

p=kc

Therefore

k=p/c

k = 120 /0.890

k=134.8

In conclusion, if p=100kpa

c=p/k

c=100/134.8

c=0.741g/l

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