The velocity of the monitor as it hits the ground is equal to 40.58 m/s.
Given the following data:
Scientific data:
- Acceleration due to gravity (g) = [tex]9.8 m/s^2.[/tex]
How to calculate the velocity.
In accordance with the law of conservation of energy, the potential energy possessed by the monitor at the roof top would be equal to the kinetic energy possessed by the monitor at the ground:
[tex]PE=KE\\\\mgh=\frac{1}{2}mv^2\\\\2mgh=mv^2\\\\V=\sqrt{2gh}\\\\V=\sqrt{2 \times 9.8 \times 84}\\\\V=\sqrt{1646.4}[/tex]
V = 40.58 m/s.
Read more on kinetic energy here: brainly.com/question/1242059
