Answered

In a constant-pressure calorimeter, the temperature of 60.0 g of water increases by 4.50 °C.
What amount of heat is transferred to the water? (Specific heat capacity of water = 4.2 J/gºC)
O A. 7.88 KJ
द
OB. 1.13 KJ
O C. 1.13 J
o D. 7.88 J

Answer :

SAMUELADESIDA43GO

The amount of heat transferred to the water if the temperature of 60.0 g of water increases by 4.50 °C is 1.134Kj.

How to calculate heat?

The quantity of heat transferred to a substance can be calculated using the following formula:

Q = mc∆T

Where;

  • Q = quantity of heat (J)
  • m = mass of substance
  • c = specific heat capacity
  • ∆T = change in temperature

According to the information in this question;

  • Q = ?
  • m = 60g
  • c = 4.2J/g°C
  • ∆T = 4.5°C

Q = 60 × 4.2 × 4.5

Q = 1134J

Therefore, the amount of heat transferred to the water if the temperature of 60.0 g of water increases by 4.50 °C is 1.134KJ.

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