CHUHUANROSEGO
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Find the equation of a line that passes through the point (4,2) that is perpendicular to the line y=(4/3)x

Answer :

GHANAMIGO

Answer:

Step-by-step explanation:

Hello:

an equation   for the line is : y =mx +b    (m: is a slope )

perpendicular to the line described by : y = 4/3 x

So : product for two slopes = -1   means : m×4/3=-1

m = -3/4

now : y = -3/4 x+b

but this line :

through the point (4,2) : 2 =(-3/4)(4)+b....... b=5

conclusion :

the equation is : y = -3/4x +5

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