Answer:
No solution
Step-by-step explanation:
[tex]\rightarrow \left \{ {{2y = 6x + 4} \atop {y = 3x - 4}} \right. \\\\[/tex]
Multiply the second equation by 2 to make the "x" coordinates the same.
[tex]\rightarrow \left \{ {{2y = 6x + 4} \atop {2(y = 3x - 4)}} \right. \\\\[/tex]
[tex]\rightarrow \left \{ {{2y = 6x + 4} \atop {2y = 6x - 8}} \right. \\\\[/tex]
Subtract 6x from the first equation with the second equation
[tex]\rightarrow \left \{ {{2y = 6x + 4} \atop {-2y = -6x + 8}} \right. \\\\[/tex]
[tex]\rightarrow 0y = 0x + 12[/tex]
Simplify the R.H.S
[tex]\rightarrow 0 \neq 12[/tex]
This system of equation has no solution.
Graph:
