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Find sin θ if θ is in Quadrant III and tan θ = -1/5

Answer :

SUMMERH36GO

Answer:= - sin( square root 8 over 3)sin(1/4)

Step-by-step explanation:

So I did (square root 8/3)(square root 15/4)+sin(1/4)cos(-1/3) divide that by (-1/3)(square root 15 over 4) - sin( square root 8 over 3)sin(1/4)

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