Kyle has a storage box that is 2 ft. Long, 3 ft. High, and has a volume of 12 ft. 3. Myla has a storage box that is 4 ft. High, 2 ft. Long, and has a volume of 16 ft. 3. What are the widths of Kyle and Myla's boxes? Explain how you know.

The widths of Kyle's and Myla's boxes for the considered case are obtained as: width of Kyle's box = 2 ft, width of Myle's box = 2 ft

How to find the volume of a right rectangular prism?

Suppose that the right rectangular prism in consideration be having its dimensions as 'a' units, 'b' units, and 'c' units, then its volume is given as:

[tex]V = a\times b \times c \: \: unit^3[/tex]

A storage box oftenly has the shape of a right rectangular prism.

We're specified that:

For Kyle's box:

Volume of the box = 12 cubic ft
Length of the box = 2 ft
Height of the box = 3 ft
Width of the box = x ft (suppose)

For Myla's box:

Volume of the box = 16 cubic ft
Length of the box = 4 ft
Height of the box = 2 ft
Width of the box = y ft (suppose)

Using the formula for volume of right rectangular prism to find the missing widths:

Case 1: For Kyle's box:

[tex]12 = 2 \times 3 \times x\\12 = 6 \times x\\\text{Dividing both the sides by 6}\\2= x\\x = 2 \: \rm ft[/tex]

Case 2: For Myla's box:

[tex]16 = 4 \times 2 \times y\\16 = 8 \times x\\\text{Dividing both the sides by 8}\\2= y\\y = 2 \: \rm ft[/tex]

Thus, the widths of Kyle's and Myla's boxes for the considered case are obtained as: width of Kyle's box = 2 ft, width of Myle's box = 2 ft

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