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Part 1. determine the molar mass of a 0.458-gram sample of gas having a volume of 1.20 l at 287 k and 0.980 atm. show your work.

part 2. if this sample was placed under extreme pressure, describe how the actual volume would compare to the predicted volume. explain your answer.

Answer :

SAMUELADESIDA43GO
  • The molar mass of 0.458-gram sample of gas having a volume of 1.20 l at 287 k and 0.980 atm is 9.15g/mol.
  • If this sample was placed under extreme pressure, the volume of the sample will decrease.

How to calculate molar mass?

The molar mass of a substance can be calculated by first calculating the number of moles using ideal gas law equation:

PV = nRT

Where;

  • P = pressure
  • V = volume
  • T = temperature
  • R = gas law constant
  • n = no of moles

0.98 × 1.2 = n × 0.0821 × 287

1.18 = 23.56n

n = 1.18/23.56

n = 0.05moles

mole = mass/molar mass

0.05 = 0.458/mm

molar mass = 0.458/0.05

molar mass = 9.15g/mol

  • Therefore, the molar mass of 0.458-gram sample of gas having a volume of 1.20 l at 287 k and 0.980 atm is 9.15g/mol
  • If this sample was placed under extreme pressure, the volume of the sample will decrease.

Learn more about gas law at: https://brainly.com/question/12667831

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