ARIANNASMITH006GO
Answered

What are the solution(s) for the quadratic equation?

f(x)=x^2+12x+36

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Answer :

Let's see

[tex]\\ \rm\rightarrowtail x^2+12x+36=0[/tex]

[tex]\\ \rm\rightarrowtail x^2+6x+6x+36=0[/tex]

[tex]\\ \rm\rightarrowtail x(x+6)+6(x+6)=0[/tex]

[tex]\\ \rm\rightarrowtail (x+6)(x+6)=0[/tex]

[tex]\\ \rm\rightarrowtail x=-6[/tex]

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