The test statistics is used to determine if the anxiety medication can happen under a null hypothesis
The test statistics that is an appropriate hypothesis test is [tex]z =\frac{0.35 - 0.40}{\sqrt{\frac{0.35(1 - 0.35)}{60} + \frac{0.40(1 - 0.40)}{85}}}[/tex]
40 milligrams of medication
Patients = 60
Lower stress level patients = 21
The mean of this medication is:
[tex]\bar x = \frac{x}{n}[/tex]
So, we have:
[tex]\bar x_1 = \frac{21}{60}[/tex]
[tex]\bar x_1 = 0.35[/tex]
75 milligrams of medication
Patients = 85
Lower stress level patients = 34
The mean of this medication is:
[tex]\bar x = \frac{x}{n}[/tex]
So, we have:
[tex]\bar x_2 = \frac{34}{85}[/tex]
[tex]\bar x_2 =0.4[/tex]
The test statistic is then calculated as:
[tex]z =\frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\bar x_1(1 - \bar x_1)}{n_1} + \frac{\bar x_2(1 - \bar x_2)}{n_2}}}[/tex]
The equation becomes
[tex]z =\frac{0.35 - 0.40}{\sqrt{\frac{0.35(1 - 0.35)}{60} + \frac{0.40(1 - 0.40)}{85}}}[/tex]
Hence, the test statistics that is an appropriate hypothesis test is [tex]z =\frac{0.35 - 0.40}{\sqrt{\frac{0.35(1 - 0.35)}{60} + \frac{0.40(1 - 0.40)}{85}}}[/tex]
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