The total work done ( W ) = 1440 J
The total heat ( Q ) = 6000 J
Given data :
Initial pressure ( Pa ) = 1 * 10⁵ pa
final pressure ( Pb ) = 1.8 * 10⁵ pa
Determine the Total work done and Heat
Considering process A --> B ( iso -choric process )
Wa -->b = 0
ΔQa --->b = nCvdT ---- ( 1 )
Note : dT = vdP / nR
equation ( 1 ) becomes
ΔQa -->b = nCv (VadP / nR )
= n( 3/2R ) [ va ( pb - pa ) / nR ]
= 3/2 * ( 0.0200 ) * ( 1.80 - 1 ) * 10⁵ pa
Δ Qab = 2400 J
Considering process B ---> C
Wb --> c = pdv
= pb ( vb - va )
Wb --> c = 1.80 * 10⁵ ( 0.0280 - 0.0200 )m³
Wbc = 1440 J
ΔQbc = nCp dT
= n(5/2 R ) ( pdv/nR )
= 5/2 [ Pb (Vb -Va) ]
= 5/2 * 1440
ΔQbc = 3600 J
Therefore :
The Total work done( W ) = Wab + Wbc
= 1440 J
Total Heat ( Q ) = ΔQab + ΔQbc
= 2400 + 3600 = 6000 J
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