6. The load-bearing piston in a certain hydraulic system has an area 70 times as large as the input piston. If the larger piston supports a load of 6160 N, how large a force must be applied to the input piston

Answer :

The force required by the input piston is 88N

Data;

  • F1 = ?
  • A1 = 1
  • A2 = 70A1
  • F2 = 6160N

Force Required on the input piston

To calculate the force required on the input piston, we can use the formula of pressure which is given as

[tex]p = \frac{force}{area} \\p = \frac{f}{a}[/tex]

since the input pressure must the equal to the output pressure,

[tex]\frac{f_1}{a_1} = \frac{f_2}{a_2} \\[/tex]

Let's substitute the values into the formula and solve

[tex]\frac{f_1}{a_1} = \frac{f_2}{a_2} \\\frac{f_1}{a_1} = \frac{6160}{70a_1} \\f_1 = \frac{6160}{70} \\f_1= 88N[/tex]

The force required by the input piston is 88N

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