Answer :
Answer:
- [tex]\tt 9.48[/tex]
Step-by-step explanation:
(1,3) and (-2,-6)
[tex]\tt Distance= \sqrt{(-6-3)^2+(-2-1)^2}[/tex]
[tex]\tt =\sqrt{9^2+3^2}[/tex]
[tex]\tt =\sqrt{81+9} =\sqrt{90}[/tex]
[tex]\tt Distance=\sqrt{90} =9.48[/tex]
Answer:
[tex]D=\sqrt{90}\ or\ D=9.49[/tex]
Step-by-step explanation:
[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\D=\sqrt{(-2-1)^2+(-6-3)^2}\\\\D=\sqrt{(-2-1)^2+(-6-3)^2} \\\\D=\sqrt{(-3)^2+(-9)^2} \\\\D=\sqrt{9+81} \\\\D=\sqrt{90}\\\\D=9.49[/tex]
Hope this helps!