The measure of m<CBD is 63 degrees
Circle Geometry
According to line geometry, the sum of angles on a straight line is expressed as:
arcCD + m<CBF = 180
Given that
arcCD= 5x + 3 and;
m<CBF = 11x - 15
Substitute
5x + 3 + 11x - 15 = 180
16x - 12 = 180
16x = 192
x = 12
Determine the measure of m<CBD
m<CBD = arc CD = 5x + 3
m<CBD = 5(12) + 3
m<CBD = 63 degrees
Hence the measure of m<CBD is 63 degrees
Learn more on circle geometry here; https://brainly.com/question/24375372
