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What is the molarity of a solution prepared by dissolving 8 grams of BaCl2 in enough
water to make a 450.0 mL solution? (Hint: must convert grams to moles first)


Answer :

Answer:

Explanation:

molar mass of BaCl2 = 208.23

mol of BaCl2 = 8/208.22

mol of BaCl2 = 0.03841905

Molarity = 0.03841905/0.450

Molarity = 0.085 M

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