Answer:
[tex]\mathsf{\sin T=\dfrac{t}{v} \ \ \ \cos T=\dfrac{u}{v}}\\\\\mathsf{\cos U=\dfrac{t}{v} \ \ \ \sin U=\dfrac{u}{v}}[/tex]
Step-by-step explanation:
Trig ratios:
[tex]\mathsf{\sin(\theta)=\dfrac{O}{H} \ \ \ \cos(\theta)=\dfrac{A}{H} \ \ \ \tan(\theta)=\dfrac{O}{A}}[/tex]
(where [tex]\theta[/tex] is the angle, O is the side opposite the angle, A is the side adjacent the angle and H is the hypotenuse of a right triangle)
[tex]\mathsf{\sin T=\dfrac{t}{v} \ \ \ \cos T=\dfrac{u}{v}}\\\\\mathsf{\cos U=\dfrac{t}{v} \ \ \ \sin U=\dfrac{u}{v}}[/tex]
