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A barrel is rolling down a hill which is at an angle of 17∘ with the horizontal. The only force acting on the barrel is the force of gravity which has a magnitude of 500 N. If the barrel rolls a total of 100 m, find the work W done on the barrel by the force of gravity. Round to two decimal places

Answer :

ABIDEMIOKINGO

The work W done on the barrel by the force of gravity is 1,461.86 Joules

Work done by an object

The formula for calculating the work done is expressed as:

W = Fd sin theta

where

  • F is the force applied = 500 N
  • d is the perpendicular distance = 10m
  • theta = 17 degrees

Substitute the given parameters into the formula to have:

W = 500(10)sin17

W = 5000sin17

W = 1,461.86 Joules

Hence the work W done on the barrel by the force of gravity is 1,461.86 Joules

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