What is the limiting reagent when 9.517 g of Fe is allowed to react with 19.34 g of water according to
the reaction given below? Base your calculations on the yield of Fe2O3. How much of the excess reagent was used and left over. The actual yield of iron(III) oxide was 1.474 g. What is the percent yield?
2 Fe + 3 H20 -› Fe203 + 3 H2