Answered

If A+B= 90°, then
[tex] \frac{\tan A \tan B + \tan A \cot B}{ \sin A \sec B } - \frac{{ \sin}^{2} B}{ \cos^{2} A} \: \text{is equal to }[/tex]
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Answer :

RIDHISHAKYA2GO

Answer:

A + B = 90° => A = 90 - B

So Tan A = Cot (90 - A) = Cot B

So Tan B = Cot (90 - B) = Cot A

SecB = Cosec (90 -B) = Cosec A

CosA = Sin (90 -A) = Sin B

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The value of the angle given regarding the tangent will be tan²A.

How to explain the angle?

From the information, TanA TanB + TanACot B/SinA SecB - Sin²B/Cos²A

= TanA CotA + TanATanA/AinA CosecA - Sin²B/Sin²B

= 1 + Tan²A - 1

= Tan²A

In conclusion, the correct option is Tan²A.

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https://brainly.com/question/25770607

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