Answer:
Where is the graph??
If a car travels from zero to 4 m/s ins 8 sec
a = 4 / 8 = .5 m/s^2
V (2) = 2 * .5 = 1 m/s after 2 sec
S = V t + 1/2 a t^2
S = 1 * 3.9 + 1/2 * 1/2 *3.9^2 = 3.9 + 3.80 = 7.70 m from 2 to 5.9 sec
Check:
Total distance traveled = 1/2 a t^2 = 5.9^2 / 4 = 8.70 m
Distance traveled in 2 sec = 1/2 * 1/2 * 4 = 1 m
Total distance from 2 to 5.9 = 8.7 - 1 = 7.7 m agreeing with thw above
