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When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass 7 kg, the acceleration of the object is [tex]8 m/s^{2}[/tex]. If the same force acts upon another object whose mass is 4 kg, what is this object's acceleration?

Answer :

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Answer:

14m/[tex]s^{2}[/tex]

Step-by-step explanation:

F = ma

Mass1:   F1 = (7kg)*(8m/[tex]s^{2}[/tex])

Mass2:  F2 = (4kg)*a

The same force, so F1 = F2

(7kg)*(8m/[tex]s^{2}[/tex]) = (4kg)*a

a = (7kg)*(8m/[tex]s^{2}[/tex])/(4kg)

a = (7/4)*(8m/[tex]s^{2}[/tex])

a = 14m/[tex]s^{2}[/tex]

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