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[tex]\boxed{\sf Trigonometry}[/tex]

Solve for x

[tex]\\ \rm\rightarrowtail tan^{-1}x+2cot^{-1}x=\dfrac{2\pi}{3}[/tex]


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Answer :

NEPALIEDUCATIONGO

Answer:

→x=√3

Step-by-step explanation:

[tex]tan^{-1} x+2cot^{-1} x=\frac{2\pi }{3} \\\\tan^{-1} x+2(\frac{\pi }{2}-tan^{-1} x)= \frac{2\pi }{3} \\\\-tan^{-1} x=\frac{2\pi }{3}-\pi \\\\-tan^{-1} x=-\frac{\pi }{3} \\\\tan^{-1} x=\frac{\pi }{3} \\\\x=tan\frac{\pi }{3} \\\\x=\sqrt{3}[/tex]

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