Answer:
32, 2√7
Explanation:
given: [tex]\sf \bold x^2+6x+2=0[/tex]
using quadratic formula: [tex]\boxed{\boxed{\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a}}}[/tex]
solve using the equation:
- [tex]\sf x_{1,\:2}=\dfrac{-6\pm \sqrt{6^2-4\cdot \:1\cdot \:2}}{2\cdot \:1}[/tex]
- [tex]\sf x_1=\dfrac{-6+2\sqrt{7}}{2\cdot \:1},\:x_2=\dfrac{-6-2\sqrt{7}}{2\cdot \:1}[/tex]
- [tex]\sf x=-3+\sqrt{7},\:x=-3-\sqrt{7}[/tex]
given a > β
- so -3+√7 > -3-√7
- a = -3+√7 and β = -3-√7
solve:
and
