is there a solving way to do this?
pick 1 and explain for brainliest

With this question we use the properties of the figures to solve

Rectangle and square have their sides being perpendicular to each other whiles rhombus and parallelogram aren’t

Also square and rhombus have their sides to be equal and opposite sides perpendicular but parallelogram and rectangle have opposite side only equal and perpendicular

Taking Q 15
W(-4,2) , X(-2,4) ,Y(0,2) and Z(-2,0)
First checking whether all sides are the same
Length of line
= √[(y2-y1)2 +(x2-x1)2]

WX= √[(4-2)2 +(-2- -4)2]
WX= √[(2)2 +(2)2]
WX= √[(4 +4)] = √8 =2 √2 units

XY = √[(2-4)2 +(0- -2)2]
XY = √[(-4)2 +(2)2] = √(16+4)
= √20 = 2 √5 units

WY = √[(2-2)2 +(0- -4)2]
WY = √16 = 4 units
Since 3 sides hv been calculated not to be equal then is none of them

Use these steps to know the others

Hope this helped

АНОНИМGO АНОНИМGO · Answer 2

Step-by-step explanation:

yes there is a distance formula

[tex]distance = \sqrt{ {(x1 - x2)}^{2} + {(y1 - y2)}^{2} } [/tex]

let me do 15th question, in this i take distance between Point W(-4,2)and X(-2,4)

WX=√[(-4 - -2)² +(2-4)²]

WX= √[(-2)²+(-2)²]

WX= √4+4

WX=√8

Similarly find XY ,YZ ,ZW you will get

XY= √8

YZ=√8

ZW=√8

ALL SIDES ARE EQUAL THAT MEANS ITS SQUARE

ALL SQUARES ARE RECTANGLE BECAUSE ITS HAVE PARALLEL SIDES AND ANGLES ARE 90°

ALL SQUARES ARE RHOMBUS BECAUSE ALL SIDES ARE EQUAL

ALL SQUARES ARE PARALLELOGRAM BECAUSE ALL SIDES ARE PARALLEL

so in this question it will be parallelogram, square, rectangle , RHOMBUS

Hope u do the same thing in 17 , 18 and 19