Answer:
Let the mass of mercury m= 13.6 gm and volume be V=1cm3.
Now change in volume when it is heated upto 50oC,
ΔV=VαΔT
ΔV=1×1.82×10−4×50
ΔV=91×10−4cm3
New volume V1=V+ΔV=1.0091cm3
New density ρ=V1m=1.009113.6=13.48gcm−3
Explanation:
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