Answer:
x > 7/4
Step-by-step explanation:
3(x + 7) < 7(x + 2)
Expand brackets: 3x + 21 < 7x + 14
Subtract 14 from both sides: 3x +7 < 7x
Subtract 3x from both sides: 7 < 4x
Divide both sides by 4: 7/4 < x
Therefore x > 7/4
[tex]\\ \tt\hookrightarrow 3(x+7)<7(x+2)[/tex]
[tex]\\ \tt\hookrightarrow 3x+21<7x+14[/tex]
[tex]\\ \tt\hookrightarrow 3x-7x<14-21[/tex]
[tex]\\ \tt\hookrightarrow -4x<-7[/tex]
[tex]\\ \tt\hookrightarrow 4x>7[/tex]
[tex]\\ \tt\hookrightarrow x>7/4[/tex]
[tex]\\ \tt\hookrightarrow x\in(\dfrac{7}{4},\infty)[/tex]
