The expression (y20)(y−5)2 is equivalent to yn. What is the value of n?.

Answer :

By using exponent properties, we will see that the expression is equivalent to:

[tex]y^{10}[/tex]

How to find the final exponent?

Here you need to remember two properties:

[tex]y^n*y^m = y^{n + m}[/tex]

[tex](y^n)^m = y^{n*m}[/tex]

Then we can rewrite our expression:

[tex]y^{20}*(y^{-5})^2[/tex]

as:

[tex]y^{20}*(y^{-5})^2 = y^{20}*y^{-5*2} = y^{20}*y^{-10} = y^{20 - 10} = y^{10}[/tex]

So the value of n is 10.

If you want to learn more about exponents, you can read:

https://brainly.com/question/11464095