[tex]\bold{\huge{\red{\underline{ Solution}}}}[/tex]
[tex]\bold{\underline{ We \: have\: given :-}}[/tex]
[tex]\sf{ 2x + 7y = 3 ...eq(1 ) }[/tex]
[tex]\sf{ x = -4y ...eq(2) }[/tex]
Here, we will use the substitution method for solving the above equations.
[tex]\bold{\underline{Subsitute \: eq(1)\:in \: eq(2)}}[/tex]
[tex]\sf{ 2(-4y) + 7y = 3 }[/tex]
[tex]\sf{ -8y + 7y = 3 }[/tex]
[tex]\sf{ - y = 3 }[/tex]
[tex]\sf{ y = - 3. ...eq( 3) }[/tex]
[tex]\bold{\underline{Subsitute \: eq(3)\:in \: eq(2)}}[/tex]
[tex]\sf{ x = -4(-3) }[/tex]
[tex]\sf{ x = 12 }[/tex]
[tex]\sf{\blue{ Hence, \: The \:value \:of \:x \:and \:y \:is\: 12\: and \:-3}}[/tex]
