Answer:
1. An oxygen molecule has three translational degrees of freedom, thus the average translational kinetic energy of an oxygen molecule at 27
∘
C is given as
E
T
=
2
3
kT=
2
3
×1.38×10
−23
×300
=6.21×10
−21
J/mol
2. An oxygen molecule has total five degrees of freedom, hence its total kinetic energy is given as
E
T
=
2
5
kT=
2
5
×1.38×10
−23
×300
=10.35×10
−21
J/mol
3. Total kinetic energy of one mole of oxygen is its internal energy, which can be given as
U=
2
f
μRT=
2
5
×1×8.314×300=6235.5J/mol1. An oxygen molecule has three translational degrees of freedom, thus the average translational kinetic energy of an oxygen molecule at 27
∘
C is given as
E
T
=
2
3
kT=
2
3
×1.38×10
−23
×300
=6.21×10
−21
J/mol
2. An oxygen molecule has total five degrees of freedom, hence its total kinetic energy is given as
E
T
=
2
5
kT=
2
5
×1.38×10
−23
×300
=10.35×10
−21
J/mol
3. Total kinetic energy of one mole of oxygen is its internal energy, which can be given as
U=
2
f
μRT=
2
5
×1×8.314×300=6235.5J/mol
