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On the return home, the cyclist accelerates from 2.0 m/s with a an acceleration of 2.2 m/s 2 . Calculate the time it takes the cyclist to reach a speed of 10m/

Answer :

INDRAWBOYGO

motion

vt=vo+at

10 m/s = 2 m/s + 2.2 m/s².t

8 = 2.2t

[tex]\tt t=\dfrac{8}{2.2}=3.63~s[/tex]

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