Answer :
So, their net force on the cart is 10 N to the right.
Introduction
Hi ! Here, I will help you with the net forces (results of forces) acting on a two-dimensional area and in opposite directions. Steps that can be taken are as follows :
- Determine where the force will go, the important thing is that you are consistent until the end.
- Count the values of the force acting, the force against the direction of your mind in number 1 is given a negative sign.
- Look at the results, if it's marked (-), then choose the opposite direction from your thoughts at number 1.
The equation for calculating the net force from this two-dimensional straight line is as follows:
[tex] \boxed{\sf{\bold{\sum F = F_1 + F_2 + ... + F_n}}} [/tex]
With the following condition :
- [tex] \sf{\sum F} [/tex] = net force (N)
- [tex] \sf{F_1} [/tex] = first force and its direction (N)
- [tex] \sf{F_2} [/tex] = second force and its direction (N)
- [tex] \sf{... + F_n} [/tex] = You can add up the force values as many times as the question (N).
Problem Solving
We know that :
In my mind, I determined that the force will go to the right. So :
- [tex] \sf{F_1} [/tex] = Jose's force = 12 N >> Because he already walk to the right.
- [tex] \sf{F_2} [/tex] = Lucy's force = 5 N >> Because she already walk to the right.
- [tex] \sf{F_3} [/tex] = John's force = -7 N >> Because he is walked to the left.
What was asked :
- [tex] \sf{\sum F} [/tex] = net force = ... N
Step by step :
[tex] \sf{\sum F = F_1 + F_2 + F_3} [/tex]
[tex] \sf{\sum F = 12 + 5 + (-7)} [/tex]
[tex] \sf{\sum F = 17 - 7} [/tex]
[tex] \boxed{\sf{\sum F = 10 \: N \: to \: the \: right}} [/tex]
Conclusion
The movement of the cart is to the right because the net force value that I calculated is not opposite (with negative sign) to the right direction. So, their net force on the cart is 10 N to the right.