Please help me on this problem !

Answer:
8.485
Step-by-step explanation:
This is a right isosceles triangle, thus the angles for side a and b are going to be the same, all the angles must all add up to equal 180, thus 180 - 90 = 90 then 90 ÷ 2 = 45 so we now know that angle a and b are 45°, with that said we can now find out what the vale of x is.
Calculates 2 sides based on 3 given angles and 1 side.
a = c·sin(A)/sin(C) = 8.48528 = 6[tex]\sqrt{2}[/tex]
b = c·sin(B)/sin(C) = 8.48528 = 6[tex]\sqrt{2}[/tex]
Area = [tex]\frac{ab·sin(C)}{2}[/tex] = 36
Perimeter p = a + b + c = 28.97056
Semiperimeter s = [tex]\frac{a + b +c}{2}[/tex] = 14.48528
Height ha = [tex]\frac{2×Area}{a}[/tex] = 8.48528
Height hb = [tex]\frac{2×Area}{b}[/tex] = 8.48528
Height hc = [tex]\frac{2×Area}{c}[/tex] = 6
Median ma = [tex]\sqrt{(a/2)^{2} + c2 - ac·cos(B)}[/tex] = 9.48683
Median mb = [tex]\sqrt{(b/2)^{2} + a2 - ab·cos(C)}[/tex] = 9.48683
Median mc = [tex]\sqrt{(c/2)^{2} + b2 - bc·cos(A)}[/tex] = 6
Inradius r = [tex]\frac{Area}{s}[/tex] = 2.48528
Circumradius R = [tex]\frac{a}{2sin(A)}[/tex] = 6