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A chef heats 400g of oil to a temperature of 113°C. The oil is left to cool until it reaches a temperature of 25°C. The oil transfers 70.4kJ of energy to its surroundings. Calculate the specific heat capacity of the oil.

Answer :

ASUWAFOHJAMESGO

The specific heat capacity of the oil is 2000 J/kg°C.

To calculate the specific heat capacity of the oil, we use the formula below.

Formula:

  • Q = cm(t₁-t₂)............... Equation 1

Where:

  • Q = Heat transfer by the oil,
  • c = Specific heat capacity of the oil
  • m = mass of the oil
  • t₁ = Initial temperature of the oil
  • t₂ = Final temperature of the oil.

Make c the subject of the equation

  • c = Q/m(t₁-t₂)................ Equation 2

From the question,

Given:

  • Q = 70.4 kJ = 70400 J
  • m = 400 g = 0.4 kg
  • t₂ = 25 °C
  • t₁ = 113 °C

Substitute these values into equation 2

  • c = 70400/0.4(113-25)
  • c = 70400/(35.2)
  • c = 2000 J/kg°C

Hence, The specific heat capacity of the oil is 2000 J/kg°C.

Learn more about specific heat capacity here: https://brainly.com/question/21406849


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