Answered

. A 225-kg crate is pushed horizontally with a force of 710 N. If the coefficient of friction is 0.20, calculate the acceleration of the crate

Answer :

ASUWAFOHJAMESGO

The acceleration of the crate is 1.196 m/s².

What is acceleration?

This can be defined as the rate of change of velocity.

To calculate the acceleration of the crate, we use the formula below.

Formula:

  • a = (F-mgμ)/m................. Equation 1

Where:

  • a = acceleration of the crate
  • m = mass of the crate
  • F = Force applied to the crate
  • μ = Coefficient of friction

From the question,

Given:

  • m = 225 kg
  • F = 710 N
  • g = 9.8 m/s²
  • μ = 0.20

Substitute the values above into equation 1

  • a = [710-(225×9.8×0.20)]/225
  • a = (710-441)/225
  • a = 269/225
  • a = 1.196 m/s²

Hence, The acceleration of the crate is 1.196 m/s²

Learn more about acceleration here: https://brainly.com/question/460763



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