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Solve the system of equations algebraically.


2x+y=5
3x−3y=3
(x,y)= (

Answer :

INDRAWBOYGO

substitution

2x+y=5

y = -2x+5 (1)

3x-3y=3 (2)

1 ⇒ 2

3x - 3(-2x+5) = 3

3x+6x-15=3

9x=18

x=2

y = -2(2)+5

y = 1

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