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You and your friend are playing moving catch with motorized catapults, where you move towards each other while passing a ball back and forth. If you are moving at 3.0 m/s, your friend is running at 3.0 m/s, and you can throw the ball at 16 m/s, how far will the ball have traveled if you start 400.0 m apart?

Answer :

ONYEBUCHINNAJIGO

The distance the ball would have traveled is 1,066.72 m.

Relative velocity

The relative velocity of two objects moving in the same or opposite direction can be used to determined the time of motion when the two objects move to a certain distance.

The time of motion of the two friends

[tex](V_a + V_b) t = d\\\\(3 + 3 ) t =400\\\\t = \frac{400}{6} \\\\t = 66.67 \ s[/tex]

The distance traveled by the ball

[tex]d = Vt\\\\d = 16\ m/s \ \ \times \ \ 66.67 \ s\\\\d = 1,066.72 \ m[/tex]

Thus, the distance the ball would have traveled is 1,066.72 m.

Learn more about relative velocity here: https://brainly.com/question/17228388

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