Answer:
[tex]We \: need \: to \: find \\ the \: differential \\ coefficient \: of \: the \\ function \: x2logxsinx \\ with \: respect \: to \: x. \\Let \: y=x \: 2logxsinx \\ We \: need \\ to \: find \: dxdy. \\Consider \\ y=x \: 2logxsinx \\ dxdy=dxd(x2)logxsinx+x2dxd(logxsinx) \\ =2x(logxsinx)+x2[sinxdxd(logx)+logxdxd(sinx)] \\ =2x(logxsinx)+x2[xsinx+logxcosx] \\ dxdy=2x(logxsinx)+xsinx+x2logxcosx[/tex]
