The half-life of Polonium-210 is 140 days. If 45 grams are present now, how much will be
present after 1 year?


Answer :

The amount of Polonium-120 present after 1 year is 7.36 grams.

Half-life:

This is the time taken for half the sample of a radioactive material to decay.

  To calculate the amount of Polonium-120 present after 1 year, we use the formula below.

Formula:

  • R' = R/([tex]2^{a/n} [/tex])................ Equation 1

Where:

  • R = Amount of Polonium-120 present now
  • R' = Amount of Polonium-120 present after 1 year
  • a = Total time
  • n = Half-life

From the question,

Given:

  • R = 45 grams
  • a = 1 year = 365 days
  • n = 40 days.

Substitute these values into equation 1

  • R' = 45/(2³⁶⁵/¹⁴⁰)
  • R' = 45/6.11
  • R' = 7.36 grams.

Hence, The amount of Polonium-120 present after 1 year is 7.36 grams

Learn more about half-life here: https://brainly.com/question/11152793

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