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Una planta es heterocigota para 2 caracteres: color de hojas y Forma de los frutos. M es para la característica dominante, hoja verde; m es el alelo para la característica recesiva, hoja amarilla. Q es el alelo para la característica dominante, fruto alargado, q es el alelo recesivo, fruto redondo. cual será la proporción fenotípica de la F2, si se cruzan estas dos plantas:

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La proporción fenotípica de la F2, si se cruzan estas dos plantas será 9:3:3:1. Los caracteres domiantes son hoja verde y fruto alargado.

Cruzamiento doble heterocigota

El cruzamiento de un doble heterocigota para dos caracteres con domiancia completa producirá una proporción fenotípica de la F2 de 9:3:3:1.

En este caso la proporción fenotípica de la F2 de 9:3:3:1 es igual a 9 individuos de hoja verde y fruto alargado, 3 individuos de hoja verde y fruto redondo, 3 individuos de hoja amarilla y fruto alargado y 1 individuo de hoja amarilla y fruto redondo.

La proporción fenotípica de la F2 puede ser calculada del mismo modo que las observaciones hechas por Mendel al observar el cruzamiento de doble heterocigotas en arveja.

Aprende más sobre doble heterocigotas aquí:

https://brainly.com/question/24418866

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