By conservation of momentum,
(110.0 kg) (1.5 ms⁻¹) + (170.0 kg) (-2.0 ms⁻¹) = (110.0 kg) (-2.75 ms⁻¹) + (170.0 kg) v
where v is the final velocity of the second car.
Solve for v :
-175 kg•ms⁻¹ = -302.5 kg•ms⁻¹ + (170.0 kg) v
127.5 kg•ms⁻¹ = (170.0 kg) v
v = (127.5 kg•ms⁻¹) / (170.0 kg) = 0.75 ms⁻¹
