y-1=-1/2(x-2)
I need this in standard form plz


Answer :

Answer:

x+2y=4

Step-by-step explanation:

Hi there!

We are given the equation y-1=-1/2(x-2), and we want to write it in standard form

Standard form is ax+by=c, where a, b, and c are free integer coefficients, but a and b cannot be zero and a cannot be negative

The equation is currently in slope-point form, which is [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1, y_1)[/tex] is a point belonging to the line

In order to get from slope-point form to standard form, we need to first simplify the equation into slope-intercept form and then convert to standard form.

Slope-intercept form is y=mx+b, where m is the slope and b is the y intercept.

So, let's convert  from slope-point form into slope-intercept form

Start by distributing -1/2 to each number on the right side

y-1=-1/2*x + -1/2*-2

y-1=-1/2x+1

Now add 1 to both sides

y=-1/2x+2

The equation is now in slope-intercept form

In standard form, x and y are on the same side, so let's add -1/2x to both sides in order to move it.

y=-1/2x+2

+1/2x +1/2x

______________

1/2x+y=2

We're almost done; remember that a, the coefficient in front of x CANNOT be negative

So let's multiply both sides by 2 in order to clear the fraction

2(1/2x+y)=2(2)

multiply

x+2y=4

Hope this helps!

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