Answer:
a. x = -1
Step-by-step explanation:
For a quadratic equation like this it is usually more easier to use the factorisation method so I'm sorry but I can't do the tables of x and y method
[tex]ax^{2} +bx+c[/tex]
In factorisation, you find a number that multiplies to give c but also adds or subtracts to give b so in this example it would be:
[tex]x^{2} +2x+1=0[/tex]
1: 1 × 1 = 1
So 1 times 1 gives 1 but then 1+1 gives 2 which is the correct match for this quadratic
[tex](x+1)(x+1)=0[/tex]
Now to solve it you take one bracket and you solve it using the 0
[tex]x+1=0\\x= -1[/tex]
Because both the equations are the same the answer would be the same
:)
