Answer:
[tex]\huge\boxed{\sf 62}[/tex]
Step-by-step explanation:
Let the two consecutive numbers be x and x + 1.
Given condition is:
x + x + 1 = 125
2x + 1 = 125
Subtract 1 to both sides
2x = 125 - 1
2x = 124
Divide 2 to both sides
x = 62
So, the numbers are:
x = 62
x + 1 = 62 + 1 = 63
So, the smallest number is 62.
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
if the sum of two consecutive numbers is 125 then the smallest number is?
62
Let the first number be x
Let the second number be x+1
=> x + x + 1 = 125
=> 2x + 1 = 125
=> 2x = 125-1
=> 2x = 124
=> x = 124/2
=> x = 62
First number = 62
Second number = x+1 = 62+1 = 63
